x+4y+4=0;x+4y+12=0

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for example:
2x+y=8
x+3y=14

Solution for x+4y+4=0;x+4y+12=0 system of equations: 


  • /| x+4*y+4 = 0| x+4*y+12 = 0
  • We try to solve the equation: x+4*y+4 = 0
  • x+4*y+4 = 0 // - x+4
  • 4*y = -(x+4) // : 4
  • y = (-(x+4))/4
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*((-(x+4))/4)+x+12 = 0| y = (-(x+4))/4
  • (4*(-x-4))/4+x+12 = 0
  • 12-4 = 0
  • 8 = 0
  • 8 = 0
  • x belongs to the empty set
  • The system of equations does not have any solution

 

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