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x+5(x+3)=3(2x+4)
We move all terms to the left:
x+5(x+3)-(3(2x+4))=0
We multiply parentheses
x+5x-(3(2x+4))+15=0
We calculate terms in parentheses: -(3(2x+4)), so:We add all the numbers together, and all the variables
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
6x-(6x+12)+15=0
We get rid of parentheses
6x-6x-12+15=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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