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x+5+x+3=-(x+4)+(3x-2)
We move all terms to the left:
x+5+x+3-(-(x+4)+(3x-2))=0
We add all the numbers together, and all the variables
2x-(-(x+4)+(3x-2))+8=0
We calculate terms in parentheses: -(-(x+4)+(3x-2)), so:We get rid of parentheses
-(x+4)+(3x-2)
We get rid of parentheses
-x+3x-4-2
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
2x-2x+6+8=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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