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x+5/2x+10=31
We move all terms to the left:
x+5/2x+10-(31)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+5/2x-21=0
We multiply all the terms by the denominator
x*2x-21*2x+5=0
Wy multiply elements
2x^2-42x+5=0
a = 2; b = -42; c = +5;
Δ = b2-4ac
Δ = -422-4·2·5
Δ = 1724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1724}=\sqrt{4*431}=\sqrt{4}*\sqrt{431}=2\sqrt{431}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-2\sqrt{431}}{2*2}=\frac{42-2\sqrt{431}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+2\sqrt{431}}{2*2}=\frac{42+2\sqrt{431}}{4} $
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