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x+5/7x=60
We move all terms to the left:
x+5/7x-(60)=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
x*7x-60*7x+5=0
Wy multiply elements
7x^2-420x+5=0
a = 7; b = -420; c = +5;
Δ = b2-4ac
Δ = -4202-4·7·5
Δ = 176260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{176260}=\sqrt{4*44065}=\sqrt{4}*\sqrt{44065}=2\sqrt{44065}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-420)-2\sqrt{44065}}{2*7}=\frac{420-2\sqrt{44065}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-420)+2\sqrt{44065}}{2*7}=\frac{420+2\sqrt{44065}}{14} $
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