x+5=(10+5)+9x2+

Solution for x+5=(10+5)+9x2+ equation:

x+5=(10+5)+9x^2+

We move all terms to the left:

x+5-((10+5)+9x^2+)=0

We add all the numbers together, and all the variables

-(15+9x^2+)+x+5=0

We get rid of parentheses

-9x^2+x-15+5-=0

We add all the numbers together, and all the variables

-9x^2+x=0

a = -9; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-9)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-9}=\frac{-2}{-18}
=1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-9}=\frac{0}{-18}
=0
$