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x+5=x(2)-7
We move all terms to the left:
x+5-(x(2)-7)=0
We add all the numbers together, and all the variables
-(+x^2-7)+x+5=0
We get rid of parentheses
-x^2+x+7+5=0
We add all the numbers together, and all the variables
-1x^2+x+12=0
a = -1; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·(-1)·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*-1}=\frac{-8}{-2} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*-1}=\frac{6}{-2} =-3 $
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