x+5x+(2/3)x=(62/3)x=180=27

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Solution for x+5x+(2/3)x=(62/3)x=180=27 equation: 



x+5x+(2/3)x=(62/3)x=180=27

We move all terms to the left:

x+5x+(2/3)x-((62/3)x)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x+5x+(+2/3)x-((+62/3)x)=0

We add all the numbers together, and all the variables

6x+(+2/3)x-((+62/3)x)=0

We multiply parentheses

2x^2+6x-((+62/3)x)=0

We multiply all the terms by the denominator


2x^2*3)x)+6x*3)x)-((+62=0

Wy multiply elements

18x^4=0

We do not support expression: x^4

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