x+5x2=26

Solution for x+5x2=26 equation:

X+5X^2=26

We move all terms to the left:

X+5X^2-(26)=0

a = 5; b = 1; c = -26;
Δ = b2-4ac
Δ = 12-4·5·(-26)
Δ = 521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{521}}{2*5}=\frac{-1-\sqrt{521}}{10}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{521}}{2*5}=\frac{-1+\sqrt{521}}{10}
$