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x+6(x-3)=4(x-3)
We move all terms to the left:
x+6(x-3)-(4(x-3))=0
We multiply parentheses
x+6x-(4(x-3))-18=0
We calculate terms in parentheses: -(4(x-3)), so:We add all the numbers together, and all the variables
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
7x-(4x-12)-18=0
We get rid of parentheses
7x-4x+12-18=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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