x+6/5+x+3/x=3

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Solution for x+6/5+x+3/x=3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+x+3/x+6/5 = 3 // - 3

x+x+3/x+6/5-3 = 0

2*x^1+3*x^-1-9/5*x^0 = 0

(2*x^2-9/5*x^1+3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-9/5*x^1+3*x^0) = 0

x^1

2*x^2+(-9/5)*x+3 = 0

2*x^2+(-9/5)*x+3 = 0

DELTA = (-9/5)^2-(2*3*4)

DELTA = -519/25

DELTA < 0

x in { } 

x belongs to the empty set

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