x+6=(x-8)(x-8)

Solution for x+6=(x-8)(x-8) equation:

x+6=(x-8)(x-8)

We move all terms to the left:

x+6-((x-8)(x-8))=0

We multiply parentheses ..

-((+x^2-8x-8x+64))+x+6=0


We calculate terms in parentheses: -((+x^2-8x-8x+64)), so:

(+x^2-8x-8x+64)

We get rid of parentheses

x^2-8x-8x+64

We add all the numbers together, and all the variables

x^2-16x+64

Back to the equation:

-(x^2-16x+64)


We add all the numbers together, and all the variables

x-(x^2-16x+64)+6=0

We get rid of parentheses

-x^2+x+16x-64+6=0

We add all the numbers together, and all the variables

-1x^2+17x-58=0

a = -1; b = 17; c = -58;
Δ = b2-4ac
Δ = 172-4·(-1)·(-58)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{57}}{2*-1}=\frac{-17-\sqrt{57}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{57}}{2*-1}=\frac{-17+\sqrt{57}}{-2}
$