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x+6=4/3x-3
We move all terms to the left:
x+6-(4/3x-3)=0
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
x-4/3x+3+6=0
We multiply all the terms by the denominator
x*3x+3*3x+6*3x-4=0
Wy multiply elements
3x^2+9x+18x-4=0
We add all the numbers together, and all the variables
3x^2+27x-4=0
a = 3; b = 27; c = -4;
Δ = b2-4ac
Δ = 272-4·3·(-4)
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{777}}{2*3}=\frac{-27-\sqrt{777}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{777}}{2*3}=\frac{-27+\sqrt{777}}{6} $
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