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x+7/10x=16
We move all terms to the left:
x+7/10x-(16)=0
Domain of the equation: 10x!=0We multiply all the terms by the denominator
x!=0/10
x!=0
x∈R
x*10x-16*10x+7=0
Wy multiply elements
10x^2-160x+7=0
a = 10; b = -160; c = +7;
Δ = b2-4ac
Δ = -1602-4·10·7
Δ = 25320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25320}=\sqrt{4*6330}=\sqrt{4}*\sqrt{6330}=2\sqrt{6330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{6330}}{2*10}=\frac{160-2\sqrt{6330}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{6330}}{2*10}=\frac{160+2\sqrt{6330}}{20} $
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