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x+7/7=1/5(5-x)
We move all terms to the left:
x+7/7-(1/5(5-x))=0
Domain of the equation: 5(5-x))!=0We add all the numbers together, and all the variables
x∈R
x-(1/5(-1x+5))+7/7=0
We add all the numbers together, and all the variables
x-(1/5(-1x+5))+1=0
We multiply all the terms by the denominator
x*5(-1x+5))-(1+1*5(-1x+5))=0
Wy multiply elements
5x^2(-+5x(-=0
We use the square of the difference formula
5x^2(-5x(-=0
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