x+8+(x-2)=(x+3)+(x+4)+(x+5)

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Solution for x+8+(x-2)=(x+3)+(x+4)+(x+5) equation:



x+8+(x-2)=(x+3)+(x+4)+(x+5)
We move all terms to the left:
x+8+(x-2)-((x+3)+(x+4)+(x+5))=0
We get rid of parentheses
x+x-((x+3)+(x+4)+(x+5))-2+8=0
We calculate terms in parentheses: -((x+3)+(x+4)+(x+5)), so:
(x+3)+(x+4)+(x+5)
We get rid of parentheses
x+x+x+3+4+5
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
We add all the numbers together, and all the variables
2x-(3x+12)+6=0
We get rid of parentheses
2x-3x-12+6=0
We add all the numbers together, and all the variables
-1x-6=0
We move all terms containing x to the left, all other terms to the right
-x=6
x=6/-1
x=-6

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