x+8+(x-2)=(x+3)+(x+4)+(x+5)

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Solution for x+8+(x-2)=(x+3)+(x+4)+(x+5) equation: 



x+8+(x-2)=(x+3)+(x+4)+(x+5)

We move all terms to the left:

x+8+(x-2)-((x+3)+(x+4)+(x+5))=0

We get rid of parentheses

x+x-((x+3)+(x+4)+(x+5))-2+8=0



We calculate terms in parentheses: -((x+3)+(x+4)+(x+5)), so:

(x+3)+(x+4)+(x+5)

We get rid of parentheses

x+x+x+3+4+5

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

2x-(3x+12)+6=0

We get rid of parentheses

2x-3x-12+6=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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