x+8/(x-2)=1+4x/(x-2)

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Solution for x+8/(x-2)=1+4x/(x-2) equation: 



x+8/(x-2)=1+4x/(x-2)

We move all terms to the left:

x+8/(x-2)-(1+4x/(x-2))=0



Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R





Domain of the equation: (x-2))!=0

x∈R



We calculate fractions


x+8x/((x-2)*(x-2)))+(-(4x*(x-1))/((x-2)*(x-2)))=0



We calculate terms in parentheses: -(4x*(x-1))/((x-2)*(x-2))), so:

4x*(x-1))/((x-2)*(x-2))

We multiply all the terms by the denominator


4x*(x-1))

We multiply parentheses

4x^2-4x^2

We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

x+8x/((x-2)*(x-2)))+(=0

We multiply all the terms by the denominator


x*((x-2)*(x-2)))+(+8x=0

We add all the numbers together, and all the variables

8x+x*((x-2)*(x-2)))+(=0

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