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x+8=1/3x-3
We move all terms to the left:
x+8-(1/3x-3)=0
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
x-1/3x+3+8=0
We multiply all the terms by the denominator
x*3x+3*3x+8*3x-1=0
Wy multiply elements
3x^2+9x+24x-1=0
We add all the numbers together, and all the variables
3x^2+33x-1=0
a = 3; b = 33; c = -1;
Δ = b2-4ac
Δ = 332-4·3·(-1)
Δ = 1101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1101}}{2*3}=\frac{-33-\sqrt{1101}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1101}}{2*3}=\frac{-33+\sqrt{1101}}{6} $
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