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x+8=1/5x
We move all terms to the left:
x+8-(1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+1/5x)+8=0
We get rid of parentheses
x-1/5x+8=0
We multiply all the terms by the denominator
x*5x+8*5x-1=0
Wy multiply elements
5x^2+40x-1=0
a = 5; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·5·(-1)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-18\sqrt{5}}{2*5}=\frac{-40-18\sqrt{5}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+18\sqrt{5}}{2*5}=\frac{-40+18\sqrt{5}}{10} $
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