x+8x-(x+4)=4(x-3)

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Solution for x+8x-(x+4)=4(x-3) equation: 



x+8x-(x+4)=4(x-3)

We move all terms to the left:

x+8x-(x+4)-(4(x-3))=0

We add all the numbers together, and all the variables

9x-(x+4)-(4(x-3))=0

We get rid of parentheses

9x-x-(4(x-3))-4=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

8x-(4x-12)-4=0

We get rid of parentheses

8x-4x+12-4=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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