x+8x-(x-4)=4(x+3)

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Solution for x+8x-(x-4)=4(x+3) equation: 



x+8x-(x-4)=4(x+3)

We move all terms to the left:

x+8x-(x-4)-(4(x+3))=0

We add all the numbers together, and all the variables

9x-(x-4)-(4(x+3))=0

We get rid of parentheses

9x-x-(4(x+3))+4=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

8x-(4x+12)+4=0

We get rid of parentheses

8x-4x-12+4=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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