x+x+(2/5)*x+(3/5)*x=3

Solution for x+x+(2/5)*x+(3/5)*x=3 equation:

x+x+(2/5)*x+(3/5)*x=3

We move all terms to the left:

x+x+(2/5)*x+(3/5)*x-(3)=0


Domain of the equation: 5)*x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+x+(+2/5)*x+(+3/5)*x-3=0

We add all the numbers together, and all the variables

2x+(+2/5)*x+(+3/5)*x-3=0

We multiply parentheses

2x^2+3x^2+2x-3=0

We add all the numbers together, and all the variables

5x^2+2x-3=0

a = 5; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·5·(-3)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*5}=\frac{-10}{10}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*5}=\frac{6}{10}
=3/5
$