x+x+(x+4)+(x+4)=28

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Solution for x+x+(x+4)+(x+4)=28 equation: 



x+x+(x+4)+(x+4)=28

We move all terms to the left:

x+x+(x+4)+(x+4)-(28)=0

We add all the numbers together, and all the variables

2x+(x+4)+(x+4)-28=0

We get rid of parentheses

2x+x+x+4+4-28=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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