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x+x+1+x+2=1+2(x+3)
We move all terms to the left:
x+x+1+x+2-(1+2(x+3))=0
We add all the numbers together, and all the variables
3x-(1+2(x+3))+3=0
We calculate terms in parentheses: -(1+2(x+3)), so:We get rid of parentheses
1+2(x+3)
determiningTheFunctionDomain 2(x+3)+1
We multiply parentheses
2x+6+1
We add all the numbers together, and all the variables
2x+7
Back to the equation:
-(2x+7)
3x-2x-7+3=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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