x+x+10+x+10x2=150

Solution for x+x+10+x+10x2=150 equation:

x+x+10+x+10x^2=150

We move all terms to the left:

x+x+10+x+10x^2-(150)=0

We add all the numbers together, and all the variables

10x^2+3x-140=0

a = 10; b = 3; c = -140;
Δ = b2-4ac
Δ = 32-4·10·(-140)
Δ = 5609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{5609}}{2*10}=\frac{-3-\sqrt{5609}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{5609}}{2*10}=\frac{-3+\sqrt{5609}}{20}
$