x+x+2+x+4=36-(x+x+2)

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Solution for x+x+2+x+4=36-(x+x+2) equation: 



x+x+2+x+4=36-(x+x+2)

We move all terms to the left:

x+x+2+x+4-(36-(x+x+2))=0

We add all the numbers together, and all the variables

x+x+x-(36-(2x+2))+2+4=0

We add all the numbers together, and all the variables

3x-(36-(2x+2))+6=0



We calculate terms in parentheses: -(36-(2x+2)), so:

36-(2x+2)

determiningTheFunctionDomain
-(2x+2)+36

We get rid of parentheses

-2x-2+36

We add all the numbers together, and all the variables

-2x+34

Back to the equation:

-(-2x+34)



We get rid of parentheses

3x+2x-34+6=0

We add all the numbers together, and all the variables

5x-28=0

We move all terms containing x to the left, all other terms to the right

5x=28

x=28/5

x=5+3/5

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