x+x+4=2(3x-6-x)+X+X

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Solution for x+x+4=2(3x-6-x)+X+X equation: 



x+x+4=2(3x-6-x)+x+x

We move all terms to the left:

x+x+4-(2(3x-6-x)+x+x)=0

We add all the numbers together, and all the variables

x+x-(2(2x-6)+x+x)+4=0

We add all the numbers together, and all the variables

2x-(2(2x-6)+x+x)+4=0



We calculate terms in parentheses: -(2(2x-6)+x+x), so:

2(2x-6)+x+x

We add all the numbers together, and all the variables

2x+2(2x-6)

We multiply parentheses

2x+4x-12

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

2x-6x+12+4=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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