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x+x+x+12=3(x+2)
We move all terms to the left:
x+x+x+12-(3(x+2))=0
We add all the numbers together, and all the variables
3x-(3(x+2))+12=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
3x-3x-6+12=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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