x+x-3+x=(6-x)2

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Solution for x+x-3+x=(6-x)2 equation: 



x+x-3+x=(6-x)2

We move all terms to the left:

x+x-3+x-((6-x)2)=0

We add all the numbers together, and all the variables

x+x+x-((-1x+6)2)-3=0

We add all the numbers together, and all the variables

3x-((-1x+6)2)-3=0



We calculate terms in parentheses: -((-1x+6)2), so:

(-1x+6)2

We multiply parentheses

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

3x+2x-12-3=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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