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x+x-35+x-46=1/2x
We move all terms to the left:
x+x-35+x-46-(1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x+x+x-(+1/2x)-35-46=0
We add all the numbers together, and all the variables
3x-(+1/2x)-81=0
We get rid of parentheses
3x-1/2x-81=0
We multiply all the terms by the denominator
3x*2x-81*2x-1=0
Wy multiply elements
6x^2-162x-1=0
a = 6; b = -162; c = -1;
Δ = b2-4ac
Δ = -1622-4·6·(-1)
Δ = 26268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26268}=\sqrt{4*6567}=\sqrt{4}*\sqrt{6567}=2\sqrt{6567}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-162)-2\sqrt{6567}}{2*6}=\frac{162-2\sqrt{6567}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-162)+2\sqrt{6567}}{2*6}=\frac{162+2\sqrt{6567}}{12} $
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