x-((x-1)/3)-((2x-5)/5)+((x+8)/6)=7

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Solution for x-((x-1)/3)-((2x-5)/5)+((x+8)/6)=7 equation:



x-((x-1)/3)-((2x-5)/5)+((x+8)/6)=7
We move all terms to the left:
x-((x-1)/3)-((2x-5)/5)+((x+8)/6)-(7)=0
We calculate fractions
x+(-6x)/()+(-12x)/()+5x/()-7=0
We multiply all the terms by the denominator
x*()+(-6x)+(-12x)+5x-7*()=0
We add all the numbers together, and all the variables
5x+x*()+(-6x)+(-12x)=0
We get rid of parentheses
5x+x*()-6x-12x=0
We add all the numbers together, and all the variables
-13x+x*()=0

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