x-(1/4)(12-x)=x+3(4-x)-2x

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Solution for x-(1/4)(12-x)=x+3(4-x)-2x equation: 



x-(1/4)(12-x)=x+3(4-x)-2x

We move all terms to the left:

x-(1/4)(12-x)-(x+3(4-x)-2x)=0



Domain of the equation: 4)(12-x)!=0

x∈R



We add all the numbers together, and all the variables

x-(+1/4)(-1x+12)-(x+3(-1x+4)-2x)=0

We multiply parentheses ..

-(-1x^2+1/4*12)+x-(x+3(-1x+4)-2x)=0

We multiply all the terms by the denominator


-(-1x^2+1+x*4*12)-((x+3(-1x+4)-2x))*4*12)=0



We calculate terms in parentheses: -((x+3(-1x+4)-2x))*4*12), so:

(x+3(-1x+4)-2x))*4*12



We get rid of parentheses

1x^2-x*4*12-((x+3(-1x+4)-2x))*4*12)-1=0

We add all the numbers together, and all the variables

x^2-x*4*12-((x+3(-1x+4)-2x))*4*12)-1=0

Wy multiply elements

x^2-48x*1-((x+3(-1x+4)-2x))*4*12)-1=0

Wy multiply elements

x^2-48x-((x+3(-1x+4)-2x))*4*12)-1=0

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