x-(2+i)(2-i)(x+3)=

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Solution for x-(2+i)(2-i)(x+3)= equation: 


Simplifying
x + -1(2 + i)(2 + -1i)(x + 3) = 0

Reorder the terms:
x + -1(2 + i)(2 + -1i)(3 + x) = 0

Multiply (2 + i) * (2 + -1i)
x + -1(2(2 + -1i) + i(2 + -1i))(3 + x) = 0
x + -1((2 * 2 + -1i * 2) + i(2 + -1i))(3 + x) = 0
x + -1((4 + -2i) + i(2 + -1i))(3 + x) = 0
x + -1(4 + -2i + (2 * i + -1i * i))(3 + x) = 0
x + -1(4 + -2i + (2i + -1i2))(3 + x) = 0

Combine like terms: -2i + 2i = 0
x + -1(4 + 0 + -1i2)(3 + x) = 0
x + -1(4 + -1i2)(3 + x) = 0

Multiply (4 + -1i2) * (3 + x)
x + -1(4(3 + x) + -1i2 * (3 + x)) = 0
x + -1((3 * 4 + x * 4) + -1i2 * (3 + x)) = 0
x + -1((12 + 4x) + -1i2 * (3 + x)) = 0
x + -1(12 + 4x + (3 * -1i2 + x * -1i2)) = 0
x + -1(12 + 4x + (-3i2 + -1i2x)) = 0

Reorder the terms:
x + -1(12 + -3i2 + -1i2x + 4x) = 0
x + -1(12 + -3i2 + -1i2x + 4x) = 0
x + (12 * -1 + -3i2 * -1 + -1i2x * -1 + 4x * -1) = 0
x + (-12 + 3i2 + 1i2x + -4x) = 0

Reorder the terms:
-12 + 3i2 + 1i2x + x + -4x = 0

Combine like terms: x + -4x = -3x
-12 + 3i2 + 1i2x + -3x = 0

Solving
-12 + 3i2 + 1i2x + -3x = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 3i2 + 1i2x + 12 + -3x = 0 + 12

Reorder the terms:
-12 + 12 + 3i2 + 1i2x + -3x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 3i2 + 1i2x + -3x = 0 + 12
3i2 + 1i2x + -3x = 0 + 12

Combine like terms: 0 + 12 = 12
3i2 + 1i2x + -3x = 12

Add '3x' to each side of the equation.
3i2 + 1i2x + -3x + 3x = 12 + 3x

Combine like terms: -3x + 3x = 0
3i2 + 1i2x + 0 = 12 + 3x
3i2 + 1i2x = 12 + 3x

Reorder the terms:
-12 + 3i2 + 1i2x + -3x = 12 + 3x + -12 + -3x

Reorder the terms:
-12 + 3i2 + 1i2x + -3x = 12 + -12 + 3x + -3x

Combine like terms: 12 + -12 = 0
-12 + 3i2 + 1i2x + -3x = 0 + 3x + -3x
-12 + 3i2 + 1i2x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
-12 + 3i2 + 1i2x + -3x = 0

The solution to this equation could not be determined.

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