x-(2x+1)=8(3x+x)

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Solution for x-(2x+1)=8(3x+x) equation: 



x-(2x+1)=8(3x+x)

We move all terms to the left:

x-(2x+1)-(8(3x+x))=0

We add all the numbers together, and all the variables

x-(2x+1)-(8(+4x))=0

We get rid of parentheses

x-2x-(8(+4x))-1=0



We calculate terms in parentheses: -(8(+4x)), so:

8(+4x)

We multiply parentheses

32x

Back to the equation:

-(32x)



We add all the numbers together, and all the variables

-33x-1=0

We move all terms containing x to the left, all other terms to the right

-33x=1

x=1/-33

x=-1/33

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