x-(2x+1)=8-(3x+3x)

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Solution for x-(2x+1)=8-(3x+3x) equation: 



x-(2x+1)=8-(3x+3x)

We move all terms to the left:

x-(2x+1)-(8-(3x+3x))=0

We add all the numbers together, and all the variables

x-(2x+1)-(8-(+6x))=0

We get rid of parentheses

x-2x-(8-(+6x))-1=0



We calculate terms in parentheses: -(8-(+6x)), so:

8-(+6x)

determiningTheFunctionDomain
-(+6x)+8

We get rid of parentheses

-6x+8

Back to the equation:

-(-6x+8)



We add all the numbers together, and all the variables

-1x-(-6x+8)-1=0

We get rid of parentheses

-1x+6x-8-1=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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