x-(2x-3)/2=1-(3x-2)/3

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Solution for x-(2x-3)/2=1-(3x-2)/3 equation: 



x-(2x-3)/2=1-(3x-2)/3

We move all terms to the left:

x-(2x-3)/2-(1-(3x-2)/3)=0

We calculate fractions


x+(-2x)/()+(-(1-(3x-2)*2)/()=0



We calculate terms in parentheses: +(-(1-(3x-2)*2)/(), so:

-(1-(3x-2)*2)/(

We multiply all the terms by the denominator


-(1-(3x-2)*2)



We calculate terms in parentheses: -(1-(3x-2)*2), so:

1-(3x-2)*2

determiningTheFunctionDomain
-(3x-2)*2+1

We multiply parentheses

-6x+4+1

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We get rid of parentheses

6x-5

Back to the equation:

+(6x-5)



We get rid of parentheses

x+(-2x)/()+6x-5=0

We multiply all the terms by the denominator


x*()+(-2x)+6x*()-5*()=0

We add all the numbers together, and all the variables

x*()+(-2x)+6x*()=0

We get rid of parentheses

x*()-2x+6x*()=0

We add all the numbers together, and all the variables

-2x+x*()+6x*()=0

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