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x-(2x-4)=-3(5-2x)+12
We move all terms to the left:
x-(2x-4)-(-3(5-2x)+12)=0
We add all the numbers together, and all the variables
x-(2x-4)-(-3(-2x+5)+12)=0
We get rid of parentheses
x-2x-(-3(-2x+5)+12)+4=0
We calculate terms in parentheses: -(-3(-2x+5)+12), so:We add all the numbers together, and all the variables
-3(-2x+5)+12
We multiply parentheses
6x-15+12
We add all the numbers together, and all the variables
6x-3
Back to the equation:
-(6x-3)
-1x-(6x-3)+4=0
We get rid of parentheses
-1x-6x+3+4=0
We add all the numbers together, and all the variables
-7x+7=0
We move all terms containing x to the left, all other terms to the right
-7x=-7
x=-7/-7
x=1
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