x-(3-x+1)=(-x)+6

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Solution for x-(3-x+1)=(-x)+6 equation: 



x-(3-x+1)=(-x)+6

We move all terms to the left:

x-(3-x+1)-((-x)+6)=0

We add all the numbers together, and all the variables

x-(-1x+4)-((-1x)+6)=0

We get rid of parentheses

x+1x-((-1x)+6)-4=0



We calculate terms in parentheses: -((-1x)+6), so:

(-1x)+6

We get rid of parentheses

-1x+6

Back to the equation:

-(-1x+6)



We add all the numbers together, and all the variables

2x-(-1x+6)-4=0

We get rid of parentheses

2x+1x-6-4=0

We add all the numbers together, and all the variables

3x-10=0

We move all terms containing x to the left, all other terms to the right

3x=10

x=10/3

x=3+1/3

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