x-(3x+16)=3(x-12)+18

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Solution for x-(3x+16)=3(x-12)+18 equation: 



x-(3x+16)=3(x-12)+18

We move all terms to the left:

x-(3x+16)-(3(x-12)+18)=0

We get rid of parentheses

x-3x-(3(x-12)+18)-16=0



We calculate terms in parentheses: -(3(x-12)+18), so:

3(x-12)+18

We multiply parentheses

3x-36+18

We add all the numbers together, and all the variables

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

-2x-(3x-18)-16=0

We get rid of parentheses

-2x-3x+18-16=0

We add all the numbers together, and all the variables

-5x+2=0

We move all terms containing x to the left, all other terms to the right

-5x=-2

x=-2/-5

x=2/5

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