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x-(4x+5)=4-2(x-5)
We move all terms to the left:
x-(4x+5)-(4-2(x-5))=0
We get rid of parentheses
x-4x-(4-2(x-5))-5=0
We calculate terms in parentheses: -(4-2(x-5)), so:We add all the numbers together, and all the variables
4-2(x-5)
determiningTheFunctionDomain -2(x-5)+4
We multiply parentheses
-2x+10+4
We add all the numbers together, and all the variables
-2x+14
Back to the equation:
-(-2x+14)
-3x-(-2x+14)-5=0
We get rid of parentheses
-3x+2x-14-5=0
We add all the numbers together, and all the variables
-1x-19=0
We move all terms containing x to the left, all other terms to the right
-x=19
x=19/-1
x=-19
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