x-(4x+5/x+7)=(4x+51/x+7)

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Solution for x-(4x+5/x+7)=(4x+51/x+7) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(4*x)-(5/x)-7 = 4*x+51/x+7 // - 4*x+51/x+7

x-(4*x)-(4*x)-(5/x)-(51/x)-7-7 = 0

x-4*x-4*x-5*x^-1-51*x^-1-7-7 = 0

-7*x^1-56*x^-1-14*x^0 = 0

(-7*x^2-14*x^1-56*x^0)/(x^1) = 0 // * x^2

x^1*(-7*x^2-14*x^1-56*x^0) = 0

x^1

-7*x^2-14*x-56 = 0

-7*x^2-14*x-56 = 0

DELTA = (-14)^2-(-56*(-7)*4)

DELTA = -1372

DELTA < 0

x in { } 

x belongs to the empty set

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