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x-(9-10)+11=12x+3(-2x+1/3)
We move all terms to the left:
x-(9-10)+11-(12x+3(-2x+1/3))=0
We add all the numbers together, and all the variables
x-(12x+3(-2x+1/3))+11-(-1)=0
We add all the numbers together, and all the variables
x-(12x+3(-2x+1/3))+12=0
We multiply all the terms by the denominator
x*3))-(12x+3(-2x+1+12*3))=0
We add all the numbers together, and all the variables
x*3))-(12x+3(-2x+37))=0
We add all the numbers together, and all the variables
-2x+x*3))-(12x+3(=0
Wy multiply elements
3x^2-2x=0
a = 3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*3}=\frac{4}{6} =2/3 $
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