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x-(9-2x)=3(x-5)
We move all terms to the left:
x-(9-2x)-(3(x-5))=0
We add all the numbers together, and all the variables
x-(-2x+9)-(3(x-5))=0
We get rid of parentheses
x+2x-(3(x-5))-9=0
We calculate terms in parentheses: -(3(x-5)), so:We add all the numbers together, and all the variables
3(x-5)
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
3x-(3x-15)-9=0
We get rid of parentheses
3x-3x+15-9=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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