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x-(x+4)=2x(x-1)
We move all terms to the left:
x-(x+4)-(2x(x-1))=0
We get rid of parentheses
x-x-(2x(x-1))-4=0
We calculate terms in parentheses: -(2x(x-1)), so:We add all the numbers together, and all the variables
2x(x-1)
We multiply parentheses
2x^2-2x
Back to the equation:
-(2x^2-2x)
-(2x^2-2x)-4=0
We get rid of parentheses
-2x^2+2x-4=0
a = -2; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·(-2)·(-4)
Δ = -28
Delta is less than zero, so there is no solution for the equation
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