x-(x-1)/(2)=2-(x+2)/(3)

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Solution for x-(x-1)/(2)=2-(x+2)/(3) equation: 



x-(x-1)/(2)=2-(x+2)/(3)

We move all terms to the left:

x-(x-1)/(2)-(2-(x+2)/(3))=0

We calculate fractions


x+(-x)/()+(-(2-(x+2)*2)/()=0



We calculate terms in parentheses: +(-(2-(x+2)*2)/(), so:

-(2-(x+2)*2)/(

We multiply all the terms by the denominator


-(2-(x+2)*2)



We calculate terms in parentheses: -(2-(x+2)*2), so:

2-(x+2)*2

determiningTheFunctionDomain
-(x+2)*2+2

We multiply parentheses

-2x-4+2

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We get rid of parentheses

2x+2

Back to the equation:

+(2x+2)



We add all the numbers together, and all the variables

x+(-1x)/()+(2x+2)=0

We get rid of parentheses

x+(-1x)/()+2x+2=0

We multiply all the terms by the denominator


x*()+(-1x)+2x*()+2*()=0

We add all the numbers together, and all the variables

x*()+(-1x)+2x*()=0

We get rid of parentheses

x*()-1x+2x*()=0

We add all the numbers together, and all the variables

-1x+x*()+2x*()=0

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