x-(y/3)=-1;-(x/8)+(y/16)=(1/2)

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2x+y=8
x+3y=14

Solution for x-(y/3)=-1;-(x/8)+(y/16)=(1/2) system of equations: 


  • /| x-(y/3)+1 = 0| y/16-(x/8)-(1/2) = 0
  • We try to solve the equation: x-(y/3)+1 = 0
  • x-1/3*y+1 = 0 // - x+1
  • -1/3*y = -(x+1) // : -1/3
  • y = (-(x+1))/(-1/3)
  • y = 3*(x+1)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (3*(x+1))/16-(x/8)-(1/2) = 0| y = 3*(x+1)
  • (3*(x+1))/16-x/8-1/2 = 0
  • 1/16*x-1/2+3/16 = 0
  • 1/16*x-5/16 = 0
  • 1/16*x-5/16 = 0 // + 5/16
  • 1/16*x = 5/16 // : 1/16
  • x = 5/16/1/16
  • x = 5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 3*(x+1): 
  • y = 3*(1+5)
  • y = 3*6
  • y = 18
  • We get a system of equations:
  • /| y = 18| x = 5

 

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