x-+(3x)+(6x-12)=180

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Solution for x-+(3x)+(6x-12)=180 equation: 



x-+(3x)+(6x-12)=180

We move all terms to the left:

x-+(3x)+(6x-12)-(180)=0

determiningTheFunctionDomain
x+3x+(6x-12)-180-=0

We add all the numbers together, and all the variables

4x+(6x-12)=0

We get rid of parentheses

4x+6x-12=0

We add all the numbers together, and all the variables

10x-12=0

We move all terms containing x to the left, all other terms to the right

10x=12

x=12/10

x=1+1/5

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