x-1+(2x-20)+(x+10)+x=36

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Solution for x-1+(2x-20)+(x+10)+x=36 equation: 



x-1+(2x-20)+(x+10)+x=36

We move all terms to the left:

x-1+(2x-20)+(x+10)+x-(36)=0

We add all the numbers together, and all the variables

2x+(2x-20)+(x+10)-37=0

We get rid of parentheses

2x+2x+x-20+10-37=0

We add all the numbers together, and all the variables

5x-47=0

We move all terms containing x to the left, all other terms to the right

5x=47

x=47/5

x=9+2/5

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