x-1+3(x+2)=1+4(x+1)

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Solution for x-1+3(x+2)=1+4(x+1) equation: 



x-1+3(x+2)=1+4(x+1)

We move all terms to the left:

x-1+3(x+2)-(1+4(x+1))=0

We multiply parentheses

x+3x-(1+4(x+1))+6-1=0



We calculate terms in parentheses: -(1+4(x+1)), so:

1+4(x+1)

determiningTheFunctionDomain
4(x+1)+1

We multiply parentheses

4x+4+1

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

4x-(4x+5)+5=0

We get rid of parentheses

4x-4x-5+5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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