x-1/2(8-x)=x+3(4-x)-x

Solution for x-1/2(8-x)=x+3(4-x)-x equation:

x-1/2(8-x)=x+3(4-x)-x

We move all terms to the left:

x-1/2(8-x)-(x+3(4-x)-x)=0


Domain of the equation: 2(8-x)!=0

x∈R


We add all the numbers together, and all the variables

x-1/2(-1x+8)-(x+3(-1x+4)-x)=0

We multiply all the terms by the denominator


x*2(-1x+8)-((x+3(-1x+4)-x))*2(-1x+8)-1=0


We calculate terms in parentheses: -((x+3(-1x+4)-x))*2(-1x+8), so:

(x+3(-1x+4)-x))*2(-1x+8

We add all the numbers together, and all the variables

-1x+(x+3(-1x+4)-x))*2(+8

Back to the equation:

-(-1x+(x+3(-1x+4)-x))*2(+8)


We add all the numbers together, and all the variables

x*2(-1x+8)-(-1x+(x+3(-1x+4)-x))*28-1=0

Wy multiply elements

2x^2(--(-1x+(x+3(-1x+4)-x))*28-1=0

We use the square of the difference formula

2x^2(+(-1x+(x+3(-1x+4)-x))*28-1=0